Count found with dif >=3 or ter >=3

Question

Hi

Is it posible to make a checker that is counting diffycult >=3 or terrain >=3, diffyculties cache?

Answer 1

Personally, I don't see the point, as those D/T ratings are on the stats page, so it's just a case of adding the totals for 3, 3.5, 4, 4.5 and 5 together.

Mine would therefore be 118 for D and 165 for T.

Comments

You have to find a number of cache with (D on 3, 3.5, 4, 4.5, 5 and the T on 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5, 5) or (D on 1, 1.5, 2, 2.5, 3, 3.5, 4, 4.5, 5 and the T on 3, 3.5, 4, 4.5, 5), not in one day, but over time.

---

Yes, which is exactly what you can add up quickly and easily using the D/T grid on the Profile Stats page :)

---

Yes I know, but not all do, and I can see, that you have 240 and not 283 as if you just add them.

---

Oh I see, you mean you want a checker that counts D >=3 AND T >=3, rather than D >=3 OR T >=3.

---

No, if you wright and, it's only thise "difficulties":[3,3.5,4,4.5,5], "terrains":[3,3.5,4,4.5,5], it is just D[1,1.5,2,2.5] T[1,1.5,2,2.5] I don't count