[Resolved] Checker request for GCAYRYB

Hi,

I need a checker for Mystery 2025 Challenge (GCAYRYB).

Requirement: The sum of (D value) x (T value) of the Mystery cache found must be greater than or equal to 2025.


Thanks,

kojy

Here is the link to a checker https://project-gc.com/Challenges/GCAYRYB/93427

Please test and reply

Sorry, that's not what I want.

For each mystery cache found, the point for the found is (D value) x (T value) of that cache.
Then sum of the points for all mystery cache found must be greater than or equal to 2025.

If I found two D2.5/T1.5 caches, three D4.0/T2.0 caches and four D5.0/T5.0 caches, the total points would be:
2*2.5*1.5 + 3*4.0*2.0 + 4*5.0*5.0 = 7.5 + 24.0 + 100.0 = 131.5

Following script output seemed not match to above requirement.

Quote

Script output
You have found:
87 T1 caches 87 points
331 T1.5 caches 496.5 points
63 T2 caches 126 points
14 T2.5 caches 35 points
11 T3 caches 33 points
6 T3.5 caches 21 points
6 T4 caches 24 points
5 T4.5 caches 22.5 points
5 T5 caches 25 points
14 D1 caches 14 points
122 D1.5 caches 183 points
115 D2 caches 230 points
109 D2.5 caches 272.5 points
79 D3 caches 237 points
23 D3.5 caches 80.5 points
32 D4 caches 128 points
19 D4.5 caches 85.5 points
15 D5 caches 75 points
Total: 2175.5 points (2025 required)

Any updates?

I made one for you

https://project-gc.com/Challenges/GCAYRYB/93673

Please test and tell us whether it is suitable for you!

Perfect.
Confirmed the output and that's what I wanted.
Thanks a lot.


kojy