[Resolved] GC3V0M6 - Multiple--Alpha, Numbers, States, Countries, etc. (needs checker)

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https://coord.info/GC3V0M6
The challenge: there are 11 categories with 12 points each. You must have a total of 120 (one hundred twenty) points out of the possible 132 points to log this cache. You need to be really oblate to find this cache, with maybe a flat spot or two. That's why it's called The Oblate Spheroid.

Round UP always

Longest Streak (measured in days): subtract 5 then divide by 5; max 12.
(STREAK - 5) / 5 = X ≤ 12

Days of the year: subtract 35 then divide by 30. For example, 366 -35 = 331 / 30 = 11+ rounds up to 12.
(FOUNDDATE - 35) / 30 = X ≤ 12

Cache Types Found: 1 point per type, max 12.
CACHETYPES = X ≤ 12

Container Types (i.e. sizes, other, virtual) Found: 1 point per type (there are 7 types) plus 1 point for the second on up to 5 types after all 7 types have been found (to make max 12).
CONTAINERTYPE = X; if X == 7 && CONTAINERTYPE > 1, X + 1 ≤ 12

Difficulty x Terrain (number of different combinations): divide by 7.
D/T / 7 = X ≤ 12

Countries: 1 point for each country; max 12.
COUNTRIES = X ≤ 12

States of the USA: 1 point for each state; max 12.
STATES = X ≤ 12

Alphabet: Caches that start with different letters of the alphabet; subtract 3, divide by 2.
NAME CONTAINS UNIQUE 1st LETTER / 2 = X ≤ 12

Numbers: Caches that contain (does not have to be at the beginning of the cache name) a different written or numeric number; max 12. Count the number in its entirety and only one number per cache.
NAME CONTAINS UNIQUE = X ≤ 12

Total caches found in a day: how many different total numbers of caches have you found in a day?; max 12. If you have cached for less than a year, you can get the numbers from the "Finds for Each Day of the Year" chart of the statistics page. Otherwise you need to scroll through your caches or use a computer program.
MOST FINDS IN DAY = X ≤ 12

Days of the year, by Placed Date: subtract 35 then divide by 30. For example, 366 -35 = 331 / 30 = 11+ rounds up to 12.
(FIND HIDDEN DATE-35)/30 = X ≤ 12

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Alphabet: Caches that start with different letters of the alphabet; subtract 3, divide by 2.
(NAME CONTAINS UNIQUE 1st LETTER-3) / 2 = X ≤ 12